Th\u1ed1ng k\u00ea soi c\u1ea7u l\u00e0 g\u00ec? Soi c\u1ea7u l\u00f4 vip l\u00e0 g\u00ec?<\/span><\/h2>\nTh\u1ed1ng k\u00ea soi c\u1ea7u<\/span><\/h3>\nTh\u1ed1ng k\u00ea soi c\u1ea7u<\/span> l\u00e0 ph\u01b0\u01a1ng ph\u00e1p nghi\u00ean c\u1ee9u c\u00e1c con s\u1ed1 theo quy lu\u1eadt nh\u1ea5t \u0111\u1ecbnh c\u1ee7a c\u00e1c chuy\u00ean gia \u0111i \u0111\u1ea7u trong ng\u00e0nh soi c\u1ea7u x\u1ed5 s\u1ed1. Ph\u01b0\u01a1ng ph\u00e1p n\u00e0y gi\u00fap cho ng\u01b0\u1eddi ch\u01a1i \u0111\u1ecbnh ra ph\u01b0\u01a1ng h\u01b0\u1edbng, con s\u1ed1 m\u00e0 m\u00ecnh s\u1eafp \u0111\u00e1nh. Tuy nhi\u00ean, ph\u01b0\u01a1ng ph\u00e1p n\u00e0y ch\u1ec9 truy\u1ec1n tai nhau qua c\u00e1c b\u1eadc ti\u1ec1n b\u1ed1i, c\u00e1c cao th\u1ee7 l\u00e3o luy\u1ec7n th\u00f4i, v\u00e0 ch\u01b0a \u0111\u01b0\u1ee3c c\u00e1c nh\u00e0 khoa h\u1ecdc n\u00e0o ch\u1ee9ng minh c\u1ea3.<\/span><\/p>\nSoi c\u1ea7u l\u00f4 VIP<\/span><\/h3>\n<\/p>\n
Kh\u00e1i ni\u1ec7m<\/span><\/strong><\/p>\nNg\u01b0\u1eddi ta th\u01b0\u1eddng d\u00f9ng ph\u01b0\u01a1ng ph\u00e1p n\u00e0y \u0111\u1ec3 soi c\u1ea7u l\u00f4 vip. Soi c\u1ea7u l\u00f4 vip c\u0169ng l\u00e0 m\u1ed9t h\u00ecnh th\u1ee9c soi c\u1ea7u th\u00f4ng th\u01b0\u1eddng. Nh\u01b0ng nh\u1eefng con s\u1ed1 n\u00e0y s\u1ebd c\u00f3 kh\u1ea3 n\u0103ng xu\u1ea5t hi\u1ec7n nhi\u1ec1u h\u01a1n \u1edf t\u1ea5t c\u1ea3 c\u00e1c gi\u1ea3i th\u01b0\u1edfng \u1edf nh\u1eefng nh\u00e0 \u0111\u00e0i. \u0110\u1eb7c bi\u1ec7t d\u00f9ng trong <\/span>th\u1ed1ng k\u00ea soi c\u1ea7u<\/span> mi\u1ec1n Nam <\/span>t\u1ef7 l\u1ec7 ch\u00ednh x\u00e1c c\u00f3 th\u1ec3 l\u00ean \u0111\u1ebfn 99%. Nguy\u00ean l\u00fd c\u1ee7a ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4 vip l\u00e0 d\u1ef1a v\u00e0o k\u1ebft qu\u1ea3 c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t 2 ng\u00e0y li\u00ean ti\u1ebfp, \u0111\u1ec3 \u0111\u00e1nh l\u00f4 \u0111\u1ec1 trong ng\u00e0y th\u1ee9 3.<\/span><\/p>\nV\u00ed d\u1ee5 ta c\u00f3 l\u00f4 \u0111\u1ec1 ng\u00e0y th\u1ee9 nh\u1ea5t l\u00e0 AB, l\u00f4 ng\u00e0y th\u1ee9 2 l\u00e0 CD.<\/span><\/p>\n-T\u1ed5ng l\u00f4 ng\u00e0y th\u1ee9 nh\u1ea5t l\u00e0: A+B = M.<\/span><\/p>\n-T\u1ed5ng l\u00f4 ng\u00e0y th\u1ee9 2 l\u00e0: C + D = N.<\/span><\/p>\n4 tr\u01b0\u1eddng h\u1ee3p trong soi c\u1ea7u l\u00f4 VIP<\/span><\/strong><\/p>\nC\u00f3 4 tr\u01b0\u1eddng h\u1ee3p x\u1ea3y ra:<\/span><\/p>\n\n- Tr\u01b0\u1eddng h\u1ee3p 1: M v\u00e0 N \u0111\u1ec1u nh\u1ecf h\u01a1n 10. Ta l\u1ea5y hi\u1ec7u: 10 \u2013 M = X, 10 \u2013 N = Y. Ta c\u00f3 l\u00f4 vip ng\u00e0y th\u1ee9 3 s\u1ebd l\u00e0 XY.<\/span><\/li>\n
- Tr\u01b0\u1eddng h\u1ee3p 2: M >, 10, N <, 10. Ta l\u1ea5y hi\u1ec7u: 20 \u2013 M = X, 10 \u2013 N = Y. Ta c\u00f3 l\u00f4 vip ng\u00e0y th\u1ee9 3 s\u1ebd l\u00e0 XY.<\/span><\/li>\n
- Tr\u01b0\u1eddng h\u1ee3p 3: M >, 10, N >, 10. Ta l\u1ea5y hi\u1ec7u: 20 \u2013 M = X, 20 \u2013 N = Y. Ta c\u00f3 l\u00f4 vip ng\u00e0y th\u1ee9 3 s\u1ebd l\u00e0 XY.<\/span><\/li>\n
- Tr\u01b0\u1eddng h\u1ee3p 4: M <, 10, N >, 10. Ta l\u1ea5y hi\u1ec7u: 10 \u2013 M = X, 20 \u2013 N = Y. Ta c\u00f3 l\u00f4 vip ng\u00e0y th\u1ee9 3 s\u1ebd l\u00e0 YX.<\/span><\/li>\n<\/ul>\n
Ch\u00fa \u00fd: N\u1ebfu t\u1ed5ng M, N l\u00e0 0 ho\u1eb7c 10 th\u00ec X, Y \u0111\u1ec1u l\u00e0 0 h\u1ebft.<\/span><\/p>\nV\u00ed d\u1ee5 c\u1ee5 th\u1ec3:<\/span><\/strong><\/em><\/p>\nNg\u00e0y th\u1ee9 nh\u1ea5t ta c\u00f3 l\u00f4 v\u1ec1 34, ng\u00e0y th\u1ee9 hai v\u1ec1 l\u00f4 48. T\u1eeb k\u1ebft qu\u1ea3 l\u00f4 v\u1ec1 2 ng\u00e0y \u0111\u00f3, ta c\u00f3: X = 10 \u2013 (3 + 4) = 3, Y = 20 \u2013 (4 + 8) = 8. K\u1ebft lu\u1eadn, ta th\u1ea5y \u0111\u00e2y thu\u1ed9c tr\u01b0\u1eddng h\u1ee3p 4, n\u00ean con l\u00f4 s\u1ebd \u0111\u00e1nh cho ng\u00e0y th\u1ee9 3 l\u00e0 83.<\/span><\/p>\n
Th\u1ed1ng k\u00ea soi c\u1ea7u<\/span> l\u00e0 ph\u01b0\u01a1ng ph\u00e1p nghi\u00ean c\u1ee9u c\u00e1c con s\u1ed1 theo quy lu\u1eadt nh\u1ea5t \u0111\u1ecbnh c\u1ee7a c\u00e1c chuy\u00ean gia \u0111i \u0111\u1ea7u trong ng\u00e0nh soi c\u1ea7u x\u1ed5 s\u1ed1. Ph\u01b0\u01a1ng ph\u00e1p n\u00e0y gi\u00fap cho ng\u01b0\u1eddi ch\u01a1i \u0111\u1ecbnh ra ph\u01b0\u01a1ng h\u01b0\u1edbng, con s\u1ed1 m\u00e0 m\u00ecnh s\u1eafp \u0111\u00e1nh. Tuy nhi\u00ean, ph\u01b0\u01a1ng ph\u00e1p n\u00e0y ch\u1ec9 truy\u1ec1n tai nhau qua c\u00e1c b\u1eadc ti\u1ec1n b\u1ed1i, c\u00e1c cao th\u1ee7 l\u00e3o luy\u1ec7n th\u00f4i, v\u00e0 ch\u01b0a \u0111\u01b0\u1ee3c c\u00e1c nh\u00e0 khoa h\u1ecdc n\u00e0o ch\u1ee9ng minh c\u1ea3.<\/span><\/p>\n <\/p>\n Kh\u00e1i ni\u1ec7m<\/span><\/strong><\/p>\n Ng\u01b0\u1eddi ta th\u01b0\u1eddng d\u00f9ng ph\u01b0\u01a1ng ph\u00e1p n\u00e0y \u0111\u1ec3 soi c\u1ea7u l\u00f4 vip. Soi c\u1ea7u l\u00f4 vip c\u0169ng l\u00e0 m\u1ed9t h\u00ecnh th\u1ee9c soi c\u1ea7u th\u00f4ng th\u01b0\u1eddng. Nh\u01b0ng nh\u1eefng con s\u1ed1 n\u00e0y s\u1ebd c\u00f3 kh\u1ea3 n\u0103ng xu\u1ea5t hi\u1ec7n nhi\u1ec1u h\u01a1n \u1edf t\u1ea5t c\u1ea3 c\u00e1c gi\u1ea3i th\u01b0\u1edfng \u1edf nh\u1eefng nh\u00e0 \u0111\u00e0i. \u0110\u1eb7c bi\u1ec7t d\u00f9ng trong <\/span>th\u1ed1ng k\u00ea soi c\u1ea7u<\/span> mi\u1ec1n Nam <\/span>t\u1ef7 l\u1ec7 ch\u00ednh x\u00e1c c\u00f3 th\u1ec3 l\u00ean \u0111\u1ebfn 99%. Nguy\u00ean l\u00fd c\u1ee7a ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4 vip l\u00e0 d\u1ef1a v\u00e0o k\u1ebft qu\u1ea3 c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t 2 ng\u00e0y li\u00ean ti\u1ebfp, \u0111\u1ec3 \u0111\u00e1nh l\u00f4 \u0111\u1ec1 trong ng\u00e0y th\u1ee9 3.<\/span><\/p>\n V\u00ed d\u1ee5 ta c\u00f3 l\u00f4 \u0111\u1ec1 ng\u00e0y th\u1ee9 nh\u1ea5t l\u00e0 AB, l\u00f4 ng\u00e0y th\u1ee9 2 l\u00e0 CD.<\/span><\/p>\n -T\u1ed5ng l\u00f4 ng\u00e0y th\u1ee9 nh\u1ea5t l\u00e0: A+B = M.<\/span><\/p>\n -T\u1ed5ng l\u00f4 ng\u00e0y th\u1ee9 2 l\u00e0: C + D = N.<\/span><\/p>\n 4 tr\u01b0\u1eddng h\u1ee3p trong soi c\u1ea7u l\u00f4 VIP<\/span><\/strong><\/p>\n C\u00f3 4 tr\u01b0\u1eddng h\u1ee3p x\u1ea3y ra:<\/span><\/p>\n Ch\u00fa \u00fd: N\u1ebfu t\u1ed5ng M, N l\u00e0 0 ho\u1eb7c 10 th\u00ec X, Y \u0111\u1ec1u l\u00e0 0 h\u1ebft.<\/span><\/p>\n V\u00ed d\u1ee5 c\u1ee5 th\u1ec3:<\/span><\/strong><\/em><\/p>\n Ng\u00e0y th\u1ee9 nh\u1ea5t ta c\u00f3 l\u00f4 v\u1ec1 34, ng\u00e0y th\u1ee9 hai v\u1ec1 l\u00f4 48. T\u1eeb k\u1ebft qu\u1ea3 l\u00f4 v\u1ec1 2 ng\u00e0y \u0111\u00f3, ta c\u00f3: X = 10 \u2013 (3 + 4) = 3, Y = 20 \u2013 (4 + 8) = 8. K\u1ebft lu\u1eadn, ta th\u1ea5y \u0111\u00e2y thu\u1ed9c tr\u01b0\u1eddng h\u1ee3p 4, n\u00ean con l\u00f4 s\u1ebd \u0111\u00e1nh cho ng\u00e0y th\u1ee9 3 l\u00e0 83.<\/span><\/p>\nSoi c\u1ea7u l\u00f4 VIP<\/span><\/h3>\n
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